The current pattern of IIT-JEE consists of two papers of three hours each. Each paper consists of Physics, Chemistry and Mathematics with equal weightage. A total of 4,79,651 students appeared for IIT_JEE 2012 conducted on 8th April 2012 which were held at 1067 centres across the country of admission to 9647 undergraduate seats .

This year PAPER-1 had 60 questions in total for 210 marks with each subject containing 20 questions, whereas PAPER-2 had 60 questions in total for 198 marks with each subject containing 20 questions.

Rank Lists for IIT-JEE 2012

Rank lists, as given below, will be prepared based on the aggregate marks obtained in IIT-JEE 2012.

l) A common rank list made up of candidates who score at least 10% in each subject and 35% in aggregate will be prepared.

2)Separate rank lists will be prepared corresponding to OBC (NCL), SC and ST categories.

3) Candidates of OBC (NCL) category must score at least 9% in each subject and 31.5% in aggregate in order to be in the OBC rank list.

4) Candidates of SC and ST categories must score at least 5% in each subject and 17.5% in aggregate in order to be in their respective rank lists.

PD Rank Lists

l) A common rank list will be prepared for PD candidates. To be in the PD rank list, candidates must score at least 5% in each subject and 17.5% in aggregate.

2) Separate PD rank lists will be prepared corresponding to the OBC (NCL), SC and ST categories. To be in these rank lists, candidates must score at least 5% in each subject and 17.5% in aggregate.

Preparatory Course Rank Lists

Separate rank lists will be prepared for preparatory course if the number of SC/ST/PD candidates in the respective rank lists is less than 1.4 times the number of seats available in the respective categories. To be in these rank lists, candidate must score at least 2.5% in each subject and 8.75% in aggregate.

For the purpose of ranking, a candidate shall be considered in all the categories in which he/she qualifies. There will be no separate waiting list of candidates.

Tie-break

The tie-break criterion, in the various rank lists, adopted for awarding ranks to the candidates who have scored the same aggregate marks is as follows:

Subject-wise average marks will be calculated for each rank list. Among the candidates having the same aggregate marks, a candidate will be ranked higher, if he/she has scored higher marks in the subject with the lowest average marks calculated as above. If there is a tie after this procedure, then the marks obtained by the tied candidates in the subject with the second-lowest average marks will be considered, and the above procedure will be repeated. Candidates tied even after this procedure will be given the same rank.