66. Since the five digit number is divisible by 3, the sum of the digits must be a multiple of 3.

Now, 0 + 1 + 2 + 3 + 4 + 5 = 15.

So the possible ways to form the 5 digit number will be given by two cases.

Case I, forming a five digit number using 0, 1, 2, 4 and 5 where the sum is 12.

The first place can be occupied by zero, so there are four ways in which the first place can be filled. The remaining four places can be filled in (4!) or 24 ways.

Number of five digit number = 4(4!) = 96.

Case II, Forming a five digit number using 1, 2, 3, 4 and 5 where the sum is 15.

Number of five digit numbers = 5! = 120.

Therefore the total number of five digit numbers that can be formed = 96 + 120 = 216 numbers. Choice (c)