SOLUTION & ANSWER FOR
VITEEE-2008 VERSION - P PART
– 1 [PHYSICS] 1. In nature,
the electric charge of any system is always– Ans: Quantisation
of charge Choice
(D) 2. The energy stored in the capacitor as shown
in
Fig.
(a) is 4.5 ´
10-
6 J. If the battery is replaced by –
Ans:
=
4.5 ´
10-
6 J
Choice (B) 3. Equal amounts of a metal are converted into
cylindrical
wires of different lengths (L) and cross-sectional –
Ans: R
=
Choice (C) 4. If the force exerted by an electric dipole
on a
charge
q at a distance of 1 m is F, the force–
Ans:
Choice (D) 5. A solid sphere of radius R
1 and
volume charge density r
=
is enclosed by a hollow sphere of radius R2
with negative surface charge density–
Ans: Q
in
=
=
=
4p
R22s
Choice (C) 6. A solid spherical conductor of radius R has
a
spherical
cavity of radius a9a < R) at its centre. A charge +Q is kept at
the center.–
Ans:
Choice (B) 7. A
cylindrical capacitor has charge Q and length L. If both –
Ans: U
1
=
U
2
=
Choice (B) 8. Three
resistances of 4 W
each are connected as shown in
figure. If the point D divides the resistance –
Ans: Choice (C) 9. The
resistance of a metal increases with increasing –
Ans: Vibration
of lattice ions increases with
temperature Choice (B) 10. In the absence
of applied potential, the electric current flowing through-
Ans: Thermal
velocity of electrons is in random
directions Choice (C) 11. A meter bridge
is used to determine the resistance of an unknown wire by measuring the balance
point length l. If the wire is
replaced by –
Ans: 12. Identify the
INCORRECT statement regarding –
Ans: Supercurrent
always flows on the surface
of
the superconductor Choice (B) 13. A sample of
HCl gas is placed in an electric field of 3 ´
104 NC-
1. The
dipole moment of each HCl molecule is –
Ans: t
= pE Choice (C) 14. When a
metallic plate swings between the –
Ans: Lenz’s
law Choice (C) 15. When an
electrical appliance is switched on, it responds almost-
Ans: Electromagnetic
waves travel with the
speed
of light Choice (B) 16. Two identical
incandescent light bulbs are connected as shown in the figure. When the circuit
is an AC voltage source–
Ans: At
resonance XL = XC Choice (B) 17. A transformer
rated at 10 kW is used to connect a 5 kV transmission line to a 240 V circuit.
The ratio –
Ans: n
=
Choice (B) 18. Three solenoid
coils of same dimension, same number of turns and same number of layers of
winding are taken. Coil 1 with inductance L1 was wound using a Mn
wire of resistance 11 W
/ m; –
Ans: Alternate
winding in opposite direction
total
flux = 0 Choice (C) 19. Light travels
with a speed of 2 ´
108 m/s in crown glass of
refractive index 1.5. What is the speed of light –
Ans: n
1v1
= n2v2 Choice (B) 20. A parallel
beam of fast moving electrons is incident normally on a narrow slit. A screen is
placed at a large distance from the slit.–
Ans: sinq
=
Choice (C) 21. Two beams of
light will not give rise to an –
Ans: Since
the polarization vectors are
perpendicular
their vector sum ą
0 Choice (C) 22. A slit of
width `a’ is illuminated with a monochromatic light of wavelength l
from a
distant source and the diffraction pattern –
Ans: sinq
=
Choice (B) 23. A thin film of
soap solution (n = 1.4) lies on the top of a glass plate (n = 1.5). When
visible light is incident almost normal to the plate, two adjacent reflection –
Ans: n
1l
1 = n2l
2
2n
1
= 3n2
Ţ
n1
= 3
d
=
= 450 Choice (B) 24. If the speed
of a wave doubles as it passes from shallow water into deeper water, –
Ans: c
= fl
Choice (C) 25. A light whose
frequency is equal to 6 ´
1014 Hz is incident on a
metal whose work function is
Ans: hu
= f
+ K.E Choice (C) 26. An electron
microscope is used to probe the atomic arrangements to a resolution of
. What should be the electric potential –
Ans:
Choice (D) 27. Which phenomenon
best supports the theory that matter –
Ans: Electrons
behave also as waves of l
=
Choice (B) 28. The
radioactivity of a certain material drops to
of the initial value in 2 hours. The half –
Ans: Activity
changes from A0 to A0/16 implies 4 half-lives. Choice (C) 29. An observer
`A’ sees an asteroid with a radioactive element moving by at a speed = 0.3 c
and measures the radioactivity decay time to be TA. Another observer
`B’ –
Ans: Moving
clocks are slower TB < TA Choice (A) 30. 234U
has 92 protons and 234 nucleons total in its nucleus. It decays by emitting an
alpha –
Ans:
234U92
ŕ
230Th90 + a
Choice (C) 31. Ka
and Kb
x-rays are emitted when there is a transition of
electron –
Ans: K
series end in n = 1 Choice (A) 32. A certain
radioactive material ZXA starts emitting a
and b
particles successively such that the end product –
Ans:
ZXA
ŕ
Z-
3YA-
8 + 2a
+ 1b
Choice (B) 33. In the circuit
shown above, an input of 1 V is fed into the inverting input of an ideal Op-amp
A. The output signal –
Ans:
= -
10 (negative feedback) Choice (B) 34. When a solid
with a band gap has a donor level just below its empty energy band, -
Ans: Knowledge
based Choice (D) 35. A p – n
junction has acceptor impurity concentration of 1017 cm-
3 in the P
side and donor impurity concentration of 1016 cm-
3 in the N
side. What is the contact potential at the –
Ans: V
contact
=
Choice (A) 36. A zener diode
has a contact potential of 1 V in the absence of biasing. It undergoes zener
breakdown for an electric field of 106 V/m at the depletion region
of p-n junction. If the width –
Ans: V
= Ed Choice (B) 37. In Colpitt
oscillator the feedback network –
Ans: a-c
equivalent circuit. Choice (B) 38. The reverse
saturation of p-n diode
Ans: Knowledge
based Choice (D) 39. A radio
station has two channels. One is AM at 1020 kHz and the other FM at 89.5 MHz. –
Ans: Knowledge
based Choice (A) 40. The
communication using optical fibers is –
Ans: Optic
fibre uses T.I.R. Choice (A) PART – II [CHEMISTRY] 41. The
oxidation number of oxygen ľ
Ans: KO
3:
+ 1 + 3x = 0, x =
Na
2O2: + 2 + 2x
= 0, x = -
1 Choice
(D) 42. Reaction
of I
Cl3 and PhMgBr ľ
Ans: Triphenyl phosphene
3C
6H5MgBr + PCl3
®
(C6H5)3P + 3MgClBr Choice
(C) 43. …….
not a characteristic of transition elements?
Ans: Choice (D) 44. Cl
-
P -
Cl bond ľ
Ans: Arial
bonds are 90° and Equatorial bonds are 120°. Choice
(A) 45. --- magnetic
moment ľ
Ans: No
unpaired electron. Choice
(A) 46. The
number of Formula units of calcium fluoride CaF2 ľ
Ans: Number
of moles =
Number
of formula units =
´
6.023
´
1023
=
1.129 ´
1024 Choice
(A) 47. The IUPAC name
of the given ľ
Ans: Choice
(C) 48. When SCN‑
is added to an aqueous ľ
Ans: Fe
3+
+ SCN‑ + H2O ®
[Fe(H2O)5SCN]2+ Choice(B) 49. Hair dyes
contain
Ans: Choice
(C) 50. Schottky
defects occurs ľ
Ans: Schottky
defect occurs when the ions have almost the same size Choice
(B) 51. The number of
unpaired electron ľ
Ans: [Co(NH
3)6]3+
-
Inner orbital complex
-
No unpaired electron [CoF
6]3‑ -
Outer
orbital complex
-
4 unpaired electrons Choice
(D) 52. The standard free energy change of a reaction ľ
Ans: -
D
G° =
2.303 RT log Kp
log Kp
0.02016 ´
103
= log Kp
= log K
p = 20.16 Choice
(A) 53. If an endothermic reaction occurs spontaneously at ľ
Ans: For
an endothermic reaction D
H is positive, the reaction occurs
spontaneously when D
S > 0 Choice
(C) 54. If a plot of log10 C versus t fives a straight line ľ
Ans: t =
t ´
= logC0 -
logC logC
= logC0 -
t ´
logC
is t in a stline with slope
Choice
(B) 55. A spontaneous process is one in which ľ
Ans: For
a spontaneous process D
G is negative. Choice
(B) 56. The half life period of a first order reaction ľ
Ans: t
˝ =
100 sec.
For a first order reaction t
˝ =
K =
=
= 6.93 ´
10‑3
sec‑1 Choice
(B) 57. The molar conductivities of KCl, NaCl and KNO3
are ľ
Ans:
=
= 128 + 111 -
152 =
87 S cm2 mol‑1 Choice
(B) 58. The electrochemical cell stops working ľ
Ans: When
both the electrode potentials become equal cell reactions stops. Choice
(B) 59. The amount of electricity required to produce ľ
Ans: 1 mole of copper is 2 equivalents
Current required = 2 Faraday Choice
(C) 60. Dipping iron article into a strongly alkaline ľ
Ans: Choice (C) 61. Hydroboration
oxidation of 4-methyl-octene ľ
Ans: Hydroboration
– oxidation of alkenes give alcohols containing the same number of carbon
atoms. Net reaction involves addition of H2O against Markownikoff’s
rule. Choice
(A) 62. When
ethyl alcohol is heated
Ans: Ethanol
undergoes dehydration when heated with conc.H2SO4 to form
ethylene. Choice
(D) 63. Anisole
is the product obtained from ľ
Ans: Anisole is phenyl methyl ether. Choice
(B) 64. Ethylene
glycol gives oxalic acid ľ
Ans: Choice (C) 65. Diamond
is hard ľ
Ans: Choice (A) 66. A
Wittig reaction with an aldehyde ľ
Ans: Carbonyl
compounds react with phosphorous yields to form alkenes. This is known as
Witting reaction. Choice
(C) 67. Cannizzaro
reaction is ľ
Ans: HCHO
does not contain a
-hydrogen atom. So it undergoes
Cannizzaro reaction. Choice
(A) 68.
ľ
Ans: C
6H6 + CO
C6H5
-
CHO This is known
as Gattermann-Koch aldehyde synthesis. Choice
(C) 69. Maleic
acid and Fumaric acids ľ
Ans: Maleic acid is the cis-isomer and fumaric
acid is the trans-isomer. Choice
(B) 70. The
gas evolved on heating ľ
Ans: HCOONa + NaOH
H
2
+ Na2CO3. Choice
(C) 71. CH
3CH3
+ HNO3 ľ
Ans: Choice (B) 72. When
acetamide is hydrolysed by ľ
Ans: Choice (A) 73. Which
will not go for diazotization?
Ans: Choice (B) 74. Secondary
nitroalkanes can be ľ
Ans:
Choice(A) 75. ……….
Stephen reduction to ľ
Ans: Alkyl
cyanides on reduction with SnCl2 and HCl will give aldehyde. Choice
(A) 76. The
continuous phase contains ľ
Ans: Choice (C) 77. The
number of hydrogen atoms present in ľ
Ans:
= 9.91 ´
1023 Choice
(B) 78. Milk
changes after digestion ľ
Ans: Choice (C) 79. ………
essential amino acids?
Ans: Choice (B) 80. …..
is a Ketohexose? Ans: Choice (C) PART – III [MATHEMATICS] 81. The system of equations -
Ans:
= 1(1 -
3) -
2(1 -
2) = -
2 + 2 = 0
Choice (B) 82.
, then -
Ans:
= I
A
4 = I
A3 = I
A-
1 A2 = I
A-
2
=
A-
1 =
=
A-
2 =
=
ab =
Ţ
a2b2 = 1 Ţ
ab = 1 Choice (D) 83. If D = diag (d1, d2,
…….., dn) where -
Ans: Choice
(D) 84. If x, y, z are different from zero and D
= -
Ans:
= 0
= 0
=
Choice (D) 85. Probability of
getting positive integral roots of the equation, -
Ans: x
= ±
n
= 1, 4, 9, 16, 25, 36
Probability
=
Choice
(C) 86. The number of real roots of equation -
Ans:
= 22 -
x4 x
4 + 20 = (22 -
x4)2 = 484 + x
8 -
44x4 x
8 -
45x4
+ 464 = 0 x
4 =
=
=
= 29, 16 x
4 = 29 is not admissible
Ţ
x4 = 16 Choice
(B) 87. Let a
, b
be the roots of the equation -
Ans: a
2-
aa
+ b = 0
A
n+1
-
aAn + bAn-
1
= a
n+1 + b
n+1-
a(a
n + b
n) + b(a
n-
1 + b
n-
1)
=
a
n-
1(a
2-
aa
+ b) + b
n-
1(b
2-
ab
+ b)
=
0
Choice
(C) 88. If the sides of a right – angle
triangle -
Ans: b,
c, a ®
AP
a =
sin B =
Choice (A) 89. The plane through the point -
Ans: x + 3y -
z = 0 y + 2z = 0 Let the plane be A(x + 1) + B(y + 1) + C(z + 1) = 0 Plane passes through the origin A + B + C = 0 Choice (A) 90.
are one of the sides -
Ans:
=
Area =
=
Choice (D) 91. If
be three unit vectors such that -
Ans
:
=
=
=
cos q
2 =
Ţ
q
2 =
cos q
1 = 0 Ţ
q
1 =
Choice (C) 92. The equation
-
Ans: Equation is
x
2 + y2 + z2
-
2xc1 -
2yc2 -
2zc3
+ h = 0
Choice (D) 93. The simplified expression of -
Ans:
Let tan-
1 x be a
Ţ
tan a
= x
Then from the figure sin a
=
Ţ
sin (tan-
1 x)
= sin
Choice (B) 94. If
-
Ans:
Ţ
z lies
on the line perpendicular to the real axis and divides the line segment between
1 and 25 in the ratio 1 : 5 Ţ
z = (5, 0) Ţ
|z| = 5 Choice (C) 95. Argument of the complex number -
Ans:
= -
(1 + i)
\
Arg
Choice
(C) 96. In a triangle ABC, the sides b and c
are -
Ans: x
2 -
61x + 820 = 0
x
2 -
41x -
20x + 820 =
0
Ţ
x1,2 = 41, 20
A = tan-
1
Ţ
cosA =
\
By
Cosine formula, a
2
= b2 + c2 -
2bc cos A a
2
= 412 + 202 -
2(41)(20)
=
2081 -
984 = 1097 Choice
(C) 97. The shortest distance between the
straight lines through -
Ans:
\
Shortest distance =
=
=
Choice
(D) 98. The center and radius of the sphere -
Ans: Centre is at
Choice (C) 99. Let A and B are two fixed points in a
plane then locus of another -
Ans: Ellipse
Choice (B) 100. The directrix of the parabola -
Ans: y
2 = -
4x -
3
= -
4
Equation of the directrix is
x
=
Choice
(D) 101. If g(x) is a polynomial satisfying g(x) -
Ans: g(x) . g(y) = g(x) + g(y) + g(xy) -
2 ľ
(1)
g(2) . g(y) = g(x) + g(y) + g(xy) -
2 5.g(y) = 5 + g(y) +
g(xy) -
2
Ţ
4g(y) =
3 + g(xy)
\
g(0) = 1 g(x) is given in a polynomial, and by the
relation given g(x) cannot be linear. Let g(x) = x2 + k Since g(0) = 1 Ţ
g(x) = x2 + 1 Verifying (1) Ţ
(x2 + 1) (y2 + 1) = x
2
+ 1 + y2 + 1 + x2y2 + 1 -
2 (1) is satisfied by
g(x) = x2 + 1
g(x) = g(3) (Q
g(x) in a polynomial) = 10 Choice
(B) 102. The value of f(0) so that -
Ans:
=
= 2
0n2 -
1 = l
n2 -
1
= f(0)
Choice (D) 103.
Let [ ] denote the greatest integer -
Ans :
f(x) is continuous at x = 0
Choice (B) 104. A spherical balloon is expanding -
Ans : Let r be
the radius and V be the volume
\
= 2 r = 5
\
V =
p
r3
= 4p
(5)2 ´
(2)
= 200 p
Choice
(C) 105. The
length of the parabola -
Ans : Length
=
=
=
=
=
=
=
=
= 2
-
=
=
=
=
=
Choice
(A) 106. If I
=
-
Ans :
I
=
Put
1 + x3 = t Ţ
x2 dx =
\
I
=
=
=
=
Choice
(D) 107. Area
enclosed by the curve -
Ans :
Ţ
= 1
\
Area of ellipse = p
ab
= p
´
= 4 Choice
(D) 108.The value of -
Ans
:
x = a sin2 q
dx = 2a sin q
cos q
dq
x = 0 ®
q
= 0
x = a ®
q
=
=
= 2a ´
Choice (C) 109.
Let y be the number of people -
Ans :
l
n y = -
kt + c
y = ce-
kt,
c > 0
k ł
0
Choice (B) 110.
The differential equation of -
Ans: x
cos q
+ y sin q
= a ľ
(1)
differentiating cos q
+ y’
sin q
= 0 ľ
(2)
Eliminating sin q
and cos
q
from (1) and (2)
cos q
=
sin q
=
sin
2
q
+ cos2 q
= 1
Ţ
Ţ
a2y’
+ a2 = (xy’ -
g)2
Ţ
Choice
(B) 111. The
differential equation
Ans:
, |y| > 0 , 3 > 0 Three
positive quantities cannot add to give zero.
\
No
solution. Choice
(B) 112.
Solution of the differential equation xdy -
Ans :
ľ
(1)
which is homogeneous put y = vx
\
\
(1) Ţ
\
x
\
Integrating
log
log
\
y +
Choice (B) 113. Let P, Q, R and S be statements and suppose-
Ans: p
®
G ®
R R ®
p and ~ S ®
R
Ţ
(C) and
(D) are not true also ~ S ®
R .
\
(A) is
not true Choice
(B) 114. In how many number of ways -
Ans : Required
number of ways =
= 2100
Choice (D) 115. If
R be a relation defined -
Ans : Relation is symmetric and transitive
Choice (D) 116. Let S be a finite set containing n
elements. Ans: For
commutative binary operations, there are
pairs available. For
each of there pairs the result of the Binary operation should be among the n
elements of S.
\
Total number of required operations =
=
Choice (B) 117. A manufacturer of cotter pins knows that-
Ans: Probability of a
cotter pin to be defective Average number of
defective cotter pins in a box of 100 is = 100 ´
=
5 We use Poisson
distribution with parameter m = 5 Choice (B)
118. The
probability that a certain kind -
Ans : p =
, q =
, n = 4
P(X = x) =
\
p(X = 2) =
=
Choice (D) 119. Mean
and standard deviation -
Ans : For best performance &
is less
Which true
for
= 75, s
= 5
Choice (B) 120. A
random variable X follows -
Ans : For Binomial distribution 0 < variance < mean 0
< b
< a
Choice
(B) PART
– IV [BIOLOGY] 121. Photosynthetic protozoan – Ans
: Euglena
is a photosynthetic protozoan. Choice (D) 122. Compound eyes –
Ans : Arthropods
possess compound eyes. Choice (D) 123. Golden age –
Ans : Reptiles
were evolved and flourished in Mesozoic era. Choice (D) 124. Match the following –
Ans : Genera
plantarum – Bentham and Hooker Species
plantarum – Linnaeus Historia Generalis plantarum – John
ray Scala
Naturae – Aristotle Choice (D) 125. Wings of mosquito, bat and bird –
Ans : Wings
in mosquito, bat and bird show convergent evolution. Choice (A) 126. Not important for evolution –
Ans : Somatic
variation never influence evolution. Choice (D) 127. Pre-zygotic isolating –
Ans: Hybrid
sterility is not a prezygotic isolation. Choice (D) 128. Evolutionary process giving rise to
new species –
Ans : Adaptive
radiation means the evolutionary process giving rise to new species adapted to
new habitats. Choice (A) 129. The principle that gives –
Ans : Hardy-Weinberg’
principle explains evolutionary process. Choice (B) 130. Polymorphic cell organelle –
Ans : Lysosome
shows primary, secondary and residual forms, hence polymorphic. Choice (B) 131. Primary oocyte on meiosis –
Ans : Each
primary oocyte on meiosis produces one ovum. Choice (A) 132. Network of protein cables –
Ans : Spindle
fibres consist protein cables. Choice (A) 133. Micelle microfibril –
Ans : Micelle
consist 100 cellulose molecules and microfibril shows 20 micelles. Choice (D) 134. In human height –
Ans : Human
height is determined by many genes, hence it is polygenic. Choice (C) 135. Cell containing multiples of 2n genomes –
Ans : Multiples
of 2n genomes result endopolyploidy. Choice (D) 136. Substitutes
one purine base with another purine –
Ans : Transition
is a kind of mutation which shows the replacement of a purine by another
purine. Choice (C) 137. Chargaff’s rule –
Ans : The
sum of purines is equal to the sum
pyramidines ie., (A)+(G) = (T)+(C). Choice (C) 138. Lysogenic cycle –
Ans : Temperate
phages show lysogenic cyclic. Choice (B) 139. Rennet –
Ans : Rennet
is used in cheese making. Choice (C) 140. Abundant immunoglobulin –
Ans : I
gG
is the most abundant immunoglobulin. Choice (A) 141. Antiviral proteins –
Ans : Viral
attack results the release of interferons. Choice (B) 142. Syngenesious –
Ans ; Stamens
of asteraceae are syngenasious, which shows anther lobes fusion and free
filaments. Choice (A) 143. Types of gametes are –
Ans ; Two
types of gametes result from TTRr. Choice (B) 144. Cross between a pure tall pea –
Ans : In
F2, the number of short plants formed are of 4. Choice (C) 145. Shaft of cilia contains –
Ans : Axoneme
is the supporting structure of cilia shaft. Choice (C) 146. Disease caused by –
Ans : Mercury
poisoning causes minamata diseases. Choice (B) 147. Starting point of –
Ans ; Ribulose
biphosphate is CO2 acceptor, hence is the starting point of Calvin
cycle. Choice (B) 148. Valve between the left atrium –
Ans : Valve
between the left atrium and the ventricle is the mitral valve. Choice (B) 149. Collecting duct of the nephron –
Ans : Collecting
duct of nephron mainly recover water. Choice (C) 150. Multiple sclerosis –
Ans : Multiple
sclerosis is an autoimmune disease. Choice (B) 151. Urinary bladder can hold –
Ans : Urinary
bladder can holds 500ml of urine, but urination desire comes when the urine is
150ml. Choice (A) 152. Chemical knives –
Ans ; Chemical
knife, Ligase is an endonuclease enzyme. Choice (A) 153. Nucleotide arrangement –
Ans : X-ray
Crystallography revealed the chemical constitution and arrangement of
nucleotide in DNA. Choice (A) 154. Common indicator organism –
Ans :
Escherichia coli grows abundantly in
polluted H2O. Choice (D) 155. Concentration of ozone –
Ans : CFCs
accumulation over north and south poles result less concentration of O3. Choice (A) 156. Reservoir of the nutrient exist –
Ans : Phosphorus
minerals exist as sedimentary. Choice (B) 157. Important fiber yielding –
Ans : Jute
fibre is obtained from Corchorus olitorius. Choice (D) 158. Karyopsis –
Ans : Karyopsis
is an one seeded dry indehiscent simple fruit. Choice (A) 159. Viruses enter –
Ans : Wounds
in the plant body facilitate the entry of viruses. Choice (B) 160. Honey –
Ans : Honey
is acidic because of the presence of large number of amino acids. Average pH of
honey is 3.1-6.1 Choice (A) CHAPTERWISE DISTRIBUTION OF QUESTIONS FOR PHYSICS
CHAPTERWISE DISTRIBUTION OF QUESTIONS FOR BIOLOGY
AREAWISE DISTRIBUTION OF QUESTIONS FOR BIOLOGY
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