SOLUTION
& ANSWER FOR KERALA MEDICAL – 2008 VERSION
– B-1 BIOLOGY 1. Match the name of the scientists – Ans: Choice (B)
– a – 3, b – 4, c – 1, d – 2 (a) Walter Sutton – Discovered the chromosomal
basis of heredity. (b) Stanley Cohen – Discovered r-DNA (c) Alexander Flemming – Discovered Penicillin. (d) James D Watson – Discovered double helical
structure of DNA. 2. The amount of usable energy which is
available for doing work –
Ans: Choice (D) – Free energy Free energy is the
energy available for doing work.
3. New Systematics introduced by Sir
Julian Huxley is –
Ans: Choice (C) – Biosystematics New systematics is also
called as biosystematics. 4. Match the following and choose the
correct –
Ans: Choice (E) – (a) – (iv), (b)
– (iii), (c) – (ii), d – (i) (a) Chrysophytes – (iv)
diatoms (b) Dinoflagellates – (iii) Gonyaulax (c) Euglenoids – (ii) Euglena (d) Protozoa – (i) Paramecium
5. Consider the following statements
regarding the major pigments –
Ans: Choice (E) – (c) is correct, but (a) and (b) are
wrong (a) Chlorophyceae –
Stored food is starch, pigments are chl.a and b. (b) Phaeophyceae – Stored food is laminarin,
pigments are chl.a and c
6. Which of the following correctly
represents –
Ans: Choice (D) – 1. – Diplontic, 2. – Haplontic, 3. –
Haplodiplontic. 1 – Diplontic
(Angiosperms and gymnosperms) 2 – Haplontic
(Spirogyra) 3 – Haplodiplontic –
(Bryophyte and pteridophyte) 7. Choose the wrong pair –
Ans: Choice (C) – Bryopsida - Anthoceros Bryopsida-mosses Anthocerotopsida – Anthoceros. 8. Which of the following is a merit in
the Bentham and Hooker’s –
Ans: Choice (D) – The placement of order Ranales in the
beginning Others are demerits of
Bentham and Hooker’s system. 9. Match the following –
Ans: Choice (B) – a – 4, b – 5, c – 1, d – 2, e – 3 (a) Cuscuta – (4) parasite (b) Eichornia – (5) root pocket (c) Monotropa – (1) saprophyte (d) Rhizophora – (2) pneumatophore (e) Utricularia – (3) insectivorous plant. 10. The correct
sequence of types of corolla in the figure –
Ans: Choice (A) – (a) Caryophyllaceous
(b) papilionaceous (c) bilabiate (d) tubular (e) bell-shaped
11. Which of the following statements –
Ans: Choice (B) – b and c only a If the stem is jointed with solid nodes
and hollow internodes, it is called culm. d Sucker is a sub aerial stem modification. e Saraca shows uniparous type of cymose
branching. Datura shows biparous types. 12. In the
monocotyledonous seeds the endosperm –
Ans: Choice (B) – Aleurone layer Aleurone layer separate
the endosperm from the embryo.
13. Match List I with List II –
Ans: Choice (A) – a – 3, b – 4, c – 1, d – 5, e – 2 (a) Spike – (3) Adhathoda (b) Capitulum – (4) Zinnia (c) Dichasial cyme – (1) Bougainvillea (d) Multiparous cyme – (5) Asclepias (e) Verticillaster – (2) Coleus 14. Which of the following represents –
Ans: Choice (C) – Trimerous, actinomorphin, polyandrous,
superior ovary, axile placentation Trimerous, Actinomorphic,
Polyandrous, 15. The botanical name of soyabean –
Ans: Choice (B) –
Glycine max (A) Arhar (B) Soyabean (C) Muliathi (D) Ratti
(E) Sem
16. Which of the following is/are not
characteristic –
Ans: Choice (C) – (c) and (d) only Ovary is bicarpellary
and inferior, placentation is basal. 17. Family Podostemaceae is placed –
Ans: Choice (A) – Multiovulatae aquaticae B – Family Piperaceae C – Family Louriaceae D – Family Euphorbiaceae E – Subclass gamopetalae 18. Match the items in Column I with Column II –
Ans: Choice (A) – a – 2, b – 3, c – 4, d – 1 (a)
Artemisia sp – (2) santonin (b)
Solidago sp – (3) dropsy (c)
Eclipta
alba – (4) tonic in spleen enlargement (d)
Chrysanthemum roseum – (1) insecticide
19. Which of the following statements –
Ans: Choice (E) – (b), (c) and (e) only (a) Collenchyma (d) Sieve tubes are devoid of nucleus at
maturity. 20. The waxy material deposited in the casparian –
Ans: Choice (B) – Suberin Suberin makes endodermis
impermeable. 21. The vascular cambial ring –
Ans: Choice (E) – Partially primary partially secondary
in origin It is partially primary
and partially secondary in origin. 22. Consider the following statements –
Ans: Choice (C) – (a) is false; but (b) and (c) are true In dicot root, the
vascular bundles are collateral and exarch.
23.Which of the following statements –
Ans: Choice (E) – (a), (b) and (d) only c-used
to observe mitochondria. e-it
is applicable to immunoelectrophoresis. 24. The method
developed by Mathew Meselson and Franklin Stahl –
Ans: Choice (C) – Buoyant Density gradient centrifugation Messelson’s and stahl’s
experiments prove semi conservative replication of DNA. 25. Which of the following is not characteristic –
Ans: Choice (D) – Outer membrane is present Outer membrane is absent
in gram-positive bacteria. 26. Match the following with correct –
Ans: Choice (A) – a – 5, b – 3, c – 1, d – 4, e – 2 (a) Endoplasmic reticulum – (5) Detoxification of
drugs (b) Spherosome – (3) Synthesis and storage of
lipids. (c) Dictyosome – (1) Stack of cisternae. (d) Peroxisome – (4) Photorespiration (e) Elaioplast – (2) Store oil and fats. 27. Read the following statements and identify –
Ans: Choice (D) – (b) and (d) are correct (a) Store and concentrate mineral salts as well
as nutrients. (c) Contain digestive enzymes with the help of
which nutrients are digested. 28. Pathogenicity of bacteria causing –
Ans: Choice (E) – Wax-D Wax-D contribute
to the pathogenecity of bacteria. 29. Which of the following statement is –
Ans: Choice (E) – (d) only Agar is a polymer of a
galactose and sulphur containing carbohydrates. 30. An example of feed back inhibition is –
Ans: Choice (C) – Allosteric inhibition of hexokinase by
glucose 6 – phosphate. A – Non-competitive
inhibition. B – Competitive
inhibition E – Competitive
inhibition
31. Pick out the correct statements –
Ans: Choice (A) – (a) only DNA replicates only one
in both mitosis and meiosis. 32. Path of water movement from soil –
Ans: Choice (B)
– Soil ®
Root hair ®
Cortex ®
Endodermis ®
Pericycle ®
Protoxylem ®
Metaxylem. Pathway of H
2O
is soil-root hair - cortex-endodermis - pericycle - protoxylem and metaxylem. 33. Which of the following statements is –
Ans: Choice (B) – (b), (c) and (d) only. K
+ plays an
important role in stomatal openings, Cohesion-Tension theory is the most
accepted theory. Soil water potential is always higher than the root cells. 34. Match the following mineral element –
Ans: Choice (C) – a – 3, b – 4, c – 5, d – 1, e – 2 Calcium – Necrosis of
young leaf Potassium – Scorched
leaf tips Iron – Chlorotic veins Zinc – Malformed leaves Phosphorus – Delayed
germination of seeds. 35. Which of the following three organelles –
Ans: Choice (B) – Chloroplast, Peroxisome, Mitochondrion. Photorespiration takes
place in chloroplast, peroxisome and mitochondria. 36. Consider the following statements –
Ans: Choice (B) – (a)
and (b) are false; but (c) is true. 400-700nm is PAR. Mn, Ca
and Cl are involved in photolysis. 37. Which of the following statements –
Ans: Choice (D) – (a) and (b) only Ps I consists P
700 38. Consider the following statements regarding –
Ans: Choice (A) – (a) and (b) are correct NADPH formation occurs
in light reaction. Mg2+ is present in porphyrin head of chlorophyll. 39. If R.Q is less than 1.0 in a respiratory –
Ans: Choice (C) – The oxidation of the respiratory
substrate consumed more oxygen than the amount of CO2 released. RQ =
40. Match the
number of carbon atoms given in List I –
Ans: Choice (C) – a – 5, b – 1, c – 4, d – 2 4.C
compound – Malic acid, 2C compound – AcetylCo.A 5C compound - a
ketoglutaric
acid, 3C compound – Pyruvate 41. Choose the correct combination of labeling –
Ans: Choice (E) – (a) Ethanol, (b) Acetaldehyde, (c) CO
2 NADH+H
+ is used in the formation of ethanol. Decarboxylation
(removal of CO2) from the pyruvate results acetal dehyde.
A –
Ethanol, b – CO2, c – acetaldehyde.
42. In which of the following reaction of
glycolysis –
Ans: Choice (D) – 2-phosphoglycerate ®
PEP. One mole of H
2O
is released from the 2-phosphoglycerate to PEP. 43. Select the correct order of endosperm types –
Ans: Choice (C) – Helobial, free nuclear, cellular.
Helobial,
free nuclear and cellular are the endosperm development.
44. Chose the mis-matched option –
Ans: Choice (D) – Birds-Adansonia – Ornithophily. Adansonia flowers are pollinated by bats (chiropterophily). 45. One hormone helps in ripening of fruits –
Ans: Choice (B) – Ethylene and abscisic acid Ethylene – fruit
ripening hormone.
Abscisic
acid – Stomatal closure.
46. Pick out the correct –
Ans: Choice (D) – (a) and (b) only Gibberellin promotes
seed germination. Low content auxin helps in the falling of immature leaves. 47. Match List I and List II–
Ans: Choice (A) – a – 3, b – 1, c – 5, d – 4, e – 2 Auxin
–Apical dominance Cytokinin – Herring
sperm DNA Gibberellin – Induces
amylase synthesis. Ethylene – Epinasty
Abscisic
acid – Inhibitor of growth.
48. Match the Column I with Column II –
Ans: Choice (D) – a – 4, b – 3, c – 1, d – 2 Camouflage – Praying
mantis Batesian mimicry –
Monarch butterfly Warning colouration –
Dendrobates pumilo
Eco
location – Horse-shoe bat.
49. Match the following with correct –
Ans: Choice (B) – (a)-(iv),
(b)-(iii), (c)-(ii), (d)-(i) Mutualism – Crab and Sea
anemone. Commensalism – Sucker
fish and Shark. Parasitism – Cuscuta and
Cissus Predation – Tiger and
Deer 50. The change in population size at a given time –
Ans: Choice (E) – Rate of immigration, natality rate,
mortality rate I – Rate of immigration,
B – Natality rate, D – Mortality rate. 51. The amount of freshwater of the earth frozen –
Ans: Choice (D) – 1.97% 1.97% amount of fresh
water is held in polar or glacial ice. 52. Which one of the following is considered –
Ans: Choice (E) – Lichen Lichen is the pioneer
community in xerarch. 53. Mercury pollution causes –
Ans: Choice (D) – Minamata disease
Mercury
pollution – Minamata disease.
54. Which of the following is not properly matched
–
Ans: Choice (E) – Mean annual temperature of earth – 25
0C Mean annual temperature
of earth is 150C. 55. Match Column I with Column II –
Ans: Choice (A) – a – 1, b – 2, c – 3, d – 4
Tropical
rain forest – Hopea.
Tropical
deciduous forest – Shorea.
Temperate
broad leaf forest – Quercus.
Temperate
coniferous forest – Picea.
56. Gaseous pollutants can be controlled by –
Ans: Choice (E) – Adsorption Adsorption is one of the
control for gaseous pollutants. 57. It is estimated
that out of the total global warming –
Ans: Choice (A) – 60%, 20%, 14% and 6% CO
2 – 60%, CH4
– 20%, CFCs – 14%, N2O – 6% 58. In the table given below, some of the
crop plants, their diseases –
Ans: Choice (A) – a-III-2, b-I-4, c-IV-1, d-II-3 Pigeon pea – Wilt – Fusarium Brinjal -Root knot – Meloidogyne Sugarcane – Red stripe –
Pseudomonas
Wheat
– Ear cockle - -Auguina.
59. Which of the following promotes
softening –
Ans: Choice (A) – Polygalacturonase Polygalacturonase enzyme
promotes softening of fruits. 60. Select the wrong statement –
Ans: Choice (C) – Regeneration of cell wall in somatic
hybridization is induced by PEG. Polyethylene Glycol
(PEG) induces the fusion of protoplast. 61. Match the scientists and their contributions in the field –
Ans: Choice (A) – i – d, ii – c, iii – a, iv – e, v – b Charles Darwin is known as the Father
of Evolution. Lamarck put forward the theory of
inheritance of acquired characters. Mutation
theory disproved Darwinism. Biogenetic law states that “Ontogeny
recapitulates phylogeny”. Germ plasm theory
disprove the theory of inheritance of acquired characters. 62. Hardy –
Weinberg equlibrium is known
–
Ans: Choice (D) – Natural
selection Natural
selection, advocates the “survival of Fittest” where organisms, who adapt well
to the changing environment, survive and reproduce to continue their
generation. 63. Industrial
melanism was highlighted–
Ans: Choice (C) – Biston
betularia Industrial
melanism is a classical example of Natural selection, that
was evident during the Industrial revolution (1920). 64. How many
pairs of cranial nerves originate –
Ans: Choice (A) – 12 Rat
has a typical
pattern of mammalian nervous system. 65. In which of
these following phyla, while the–
Ans: Choice (D) – Echinoderms An
example of echinoderm larva is bipinneria larva which shows bilateral symmetry. 66. Match List I
with List II
and select
the–
Ans: Choice (C) – a – 3, b
– 4, c – 5, d – 2, e – 1 Cnidarians
are otherwise called coelenterates (eg:Hydra), Pennatula
is commonly called sea pen. Wuchereria brancrofti is the causative agent of Filariasis. 67. The number
of gills present in–
Ans: Choice (D) – 4 pairs Osteichthyes, commonly called bony fishes. Some of them such
as Anabas, Clarius have accessory respiratory structure. 68. The number
of abdominal segments in male–
Ans: Choice (A) – 10, 10 The
abdominal segments are laterally provided with openings called spiracles, which
facilitates the respiratory gas exchange. 69. In
earthworm, the characteristic internal median–
Ans: Choice (C) – 26 to 35
segements Typhlosole, is analogous to the intestinal microvilli and
helps increase the surface area of absorption. 70. Select the
correct order of classification of Rana–
Ans: Choice (B) – Chordata,
Craniata, Gnathostomata, Amphibia, Rana
Rana tigrina and Rana hexadactyla are the common species of Indian frogs. 71. The cloaca
in frog is a common chamber for –
Ans: Choice (A) – Alimentary
canal In
higher animals (viz; humans), the urinary and germinal openings are separate.
The alimentary canal opens out through the anus. 72. The alveoli
of lungs are lined by–
Ans: Choice (B) – Squamous
epithelium Squamous
epithelium, are made of flat polygonal cells, which are nucleated and also
called pavement epithelium. It is thin and facilitalis easy diffusion of gases.
73. The type of
cell junction which facilitates –
Ans: Choice (C) – Gap
junction Tight
junctions helps the substances from being leaked across the tissues.,
and adhering junctions keeps neighboring cells together. 74. The phenomenon of a single gene
regulating several–
Ans: Choice (D) –
Pleiotropism Skin
colour inheritance in man and coat colour in mice are
example of pleiotropism.
75. Inheritance
of blood group is a –
Ans: Choice (E) – I
, III
The
phenomenon by which two or more allcles of a genes
inherit as a single unit is called multiple allilism. Codominance is a
phenomenon in which there is noi dominant recessive relationship between
alleles of a gene. 76. When a dihybrid cross is fit into
a Punnett square with–
Ans: Choice (D)– 16 Dihybrid cross, in a cros involving two pairs of contrasting
characters of trait. Mendelian dihybrid ratio is 9:3:3:1 77. Sex chromosomes of a female bird
are represented –
Ans: Choice (E)–ZW The
sex determination of birds in ZZ- Zw (Female heterogamety). 78. A man can
inherit his X chromosome from–
Ans: Choice (A) – His
material grand father
only
This
inheritance of X chromosome from maternal grand mother or grandfather to
grandson through mother is called criss – cross or Zig – Zag inheritance. 79. Match the human genetic disorder
with the causative–
Ans: Choice (D) – a-3, b-1,
c-5, d-2, e-4 -
Sickle cell anaemia is caused due to defective
haemoglobin (Hbs) -
Colour – blindness is the inability to alifferentiat
between primary colour (X- linked inhertitance) -
Phemylketomuria is an inborn cross in metabolism in
which ketone bodies are excreted through urine. -
Huntington’s disease is a nervous disorder. 80. When a
mutation is limited to the substitution of one–
Ans: Choice (B) – substitution
of one nucleotide by another Sickle
cell anaemia is an example for point mutation. 81. Cri-du-chat
(cry of the cat) syndrome occurs–
Ans: Choice (A) – Deletion Cridu-
chat’s syndrome is characterized by deletion of a part of the short arm of the
5th chromosome. 82. Down’s
syndrome is an–
Ans: Choice (A) – Aneuploidy Down’s
synodrome (Mongolism) is caused duct the Trisomy of the 21st
chromosome. 83. In a
pedigree analysis, —
= O–
Ans: Choice (B) –
Consanguinous mating Consanguineous
mating is the mating between close relatives. 84. Which of
these is not a Mendelian disorder?–
Ans: Choice (E) – Turner’s
syndrome Turner’s
syndrome (XO- females) is a chromosomal disorder. Other are
genetic or mendelian disorders. 85. The haploid
content of human DNA–
Ans: Choice (A) – 3.3 ´
109
bp
E.
coli has
4.6
´
106
bp and ttman haploid DNA content is 3.3´
109 bp., which indicates that there is
no relation between DNA content and complesity of organism. 86. Gynaecomastia
is a symptom of–
Ans: Choice (B) –
Klinefelter’s syndrome Gynacomastia
is a condition characteriased by the appearance of female characters in male. 87. The
distance between the genes a, b, c and d–
Ans: Choice (E) – abcb In
a gene map, the distance between genes are expressed
in centimorgan units. 88. Meselson
and Stahl experiment–
Ans: Choice (D) – In
semi-conservative replication one of the parental stranel of DNA, is conserved
in each daughter. 89. Match List I
with List II
and
select–
Ans: Choice (C) –
Transfornation Bt toxin is coded by the cry gene. nif genes are
nitrogen fixing genes. Artificial
human insulin developed by rDNA technology is called humulin.
Psenclomonas putida are oil-eating bacteria.
Trichoderma
is used as blood-cholesterol lowering agents 90. The
construction of the first recombinant DNA–
Ans: Choice (B) –
Salmonella typhimurium
Salmonella typhi is the consative agent of typhoid fever. 91. The basis
of DNA fingerprinting–
Ans: Choice (C) –
Polymorphism in sequence DNA
finger printing is based on identifying differences in some specific regions in
DNA sequence called repetitive DNA. Polymorphism arises due to mutation in the
germ cells. 92. Statements–
Ans: Choice (B) – 1 and 3 are correct but 2
and 4 are wrong 2.
Vitamin B6 is known as Pyridoxine 93. `Crypts of
Lieberkuhn’ –
Ans: Choice (D) –
Intestinal tracts Crypts
of Lieberkuhn are glands found in small Intestine between the villi. 94. Glisson’s
capsule is associated with–
Ans: Choice (A) – Liver Each
lobule of the kidney covered by a thin sheath of connective tissue called
glisson’s capsule. 95. The main
digestive function of enterokinase is–
Ans: Choice (C) –
Conversion of trypsinogen into trysin Renin
converts Casein to Paracasein HCl converts Pepsinogen to Pepsin Gastrin
stimulates gastric glands to secrete gastric juice 96. In which of
these animals, antennal gland–
Ans: Choice (D) – Prawn Human
beings – Kidney Cockroach –
Malpighian tubules Planaria
– Flame cells Earth
worm
– Metanephridia 97. About 97%
of O2 is transported by RBC–
Ans: Choice (A) – Dissolved
in plasma and transported 97%
of O2 is transported by RBC as Oxyhaemoglobin 98. The diagram represents the human
larynx. Choose–
Ans: Choice (D) – (a)- Epiglottis, (b) – Thyroid, (c) – Tracheal cartilage, (d)
Trachea Larynx
is known as voice box. Epiglottis cover the glottis
and prevents the entry of food into larynx. Thyroid
glands are present on either sides of the trachea. Tracheal
cartilage support trachea. Trachea
is known as the wind pipe. 99. Histamine
and heparin are secreted–
Ans: Choice (E) – Basophils Histamine
and heparin secreted by Basophils help in inflammatory reaction. Monocytes
& neutrophils are phagocytic. Eosinophils
are associated with allergic reaction. 100. In the thin
filament of skeletal muscle fibre,–
Ans: Choice (D)
– Troponin G-actin
is known as globular actin. Actin is a contractile protein which forms the thin
filament. Tropomyosin
is a protein associated with Actin filament. It lies in the grooves of the
helically coiled Actin filament. Myosin
is the contractile protein which forms the thick filament 101. Open
circulatory system is present–
Ans: Choice (E)
– I
only In
annelids & Chordates circulatory system is closed. Except
Cephalopods, all molluses have closed circulatory system. 102. JG cells,
under low glomerular blood–
Ans: Choice (C)
– Renin Renin
is an enzyme which converts the protein Angiotensinogen to a peptide hormone. Angiotensin II
, which
increases the blood pressure and volume. Aldosterone
is secreted by adrenal cortex. ADH is secreted by the hypothalamus. It
increases the reabsorption of water in the kidney. 103. The opening
of right atrium into right ventricle–
Ans: Choice (E)
– Tricuspid valve Mitral/bicuspid
valve guards the left auriculo –ventricular opening Pulmonary
semilunar valve guards the opening of right ventricle into the pulmonary
artery. Aortic semilunar valve guards the opening of left ventricle into the
aorta. 104. The pineal
gland secretes–
Ans: Choice (C)
– Melatonin Vasopressin
is secreted by Hypothalamus Melanin
– skin pigment MSH
– intermediate lobe of pituitary Prolactin
– Anterior lobe of pituitary 105. In the
pelvic girdle of man–
Ans: Choice (B)
– a-ilium, b-acetabulum c-pubis, d-ischium, e-pubic symphysis. Acetabulum
– cavity into which head of the femur fits Pubis
and Ischium – bones that form the pelvic girdle
Pubis symphysis – Line of fusion where the two halves of pelvic
girdle meet.
106. Proximal
convoluted tubule–
Ans: Choice (C)
– Simple cuboidal brush border epithelium PCT
of nephron is lined by simple cuboidal brush border epithelicum
107. Match List I
with List II
–
Ans: Choice (A)
– a-2, b-5, c-4, d-1, e-3 Adrenalin
– secreted by Adrenal gland – accelerated heart beat
Hyperparathyroidism –due to malfunctioning of parathyroid gland.
-
demineralisation of bones Oxytocin –
secreted by pituitary – stimulates contraction of uterus during child birth Hypothyroidism
– malfunctioning of thyroid gland - causes myxoedema in adults and cretinism in
children 108. Which of
the following animal –
Ans: Choice (E)
– Cockroach Tapeworm,
Leech, Sponge and Earthworm are bisexual. 109. In a
Myelinated neuron, two adjacent–
Ans: Choice (A)
– Nodes of Ranvier Synaptic
cleft is the gap between two adjacent nerve cells. Schwann cells is a type of glial cell wrapped around the
axon of neuron, thus covering the axon with insulating plasma membrane synaptic
knob is the terminal end of axon. Neural plate formed during the embryonic
stage. 110. Fovea in
the eye is a central pit in–
Ans: Choice (D)
– Macula lutea Blind
spot is the region in the retina of eye where the optic nerves leave. Retina
is the photosensitive layer of the eye. Cornea is the transparent part of
sclera. Choroid is the middle opaque layer of eye. 111. The
potential maintained across the neuron–
Ans: Choice (B)
– –70 mV
e
70 mV is
the potential difference in a resting neuron due to the differential
distribution of Na+ and K+ across the membrane. The
negative sign indicates that the inside is negative relative to the outside. 112. Match List I
with List II
and –
Ans: Choice (E)
– a-5, b-4, c-1, d-2 Coccygeal
nerves – 1 pair Cervical
nerves – 8 pairs Thoracic
nerves – 12 pairs Sacral
nerve – 5 pairs 113. A typical
angiosperm embyo sac–
Ans: Choice (B)
– 8 nucleate – 7 celled Embryosac
at maturity has 8 nuclei 3 antipodal cell, 2 synergids, 1 egg and 2 polar
nuclei present in a single cell. 114. Spermatids
are transformed–
Ans: Choice (E)
– Spermiogenesis Spermiation
– release of sperms from seminiferous tubules Spermatogenesis
- formation of sperms Meiosis
– reductional cell division 115. Habitat
loss and fragmentation, over–
Ans: Choice (C)
– Biodiversity loss Population
explosion – rapid growth in population
Migration –
movement of organisms from one place to another during unfavourable conditions Pollution
– undesirable change in air, water or land Ecological
succession – successive replacement of communities in a given area over a
period of time 116. The venue
and year of the Earth Summit on–
Ans: Choice (B)
– Rio de Jeneiro, 1992 117. Neurasthenia
refers–
Ans: Choice (D)
– Mental inability to concentrate on or enjoy things Hypochondria
– undue concern about Human health Post
traumatic stress disorder – traumatic experience of rape Hallucination
– disorder of sensory
perception
Mood
disorders – mood upswings
118. Diacetyl
morphine is–
Ans: Choice (C)
– Heroin Morphine
– opiate narcotic
painkiller Cannabis
and Hashish – Hallucinogens Coccaine
- Stimulant
119. Choose the
wrong statement–
Ans: Choice (E)
– The time-lag between the infection and appearance of AIDS symptom may vary from few
hours to a week. The
time – lag between the infection and appearance of AIDS symptom m ay vary from few months to many years 120. The cancer
of the epithelial cells–
Ans: Choice (E)
– Carcinoma Leukemia
– blood cancer Sarcoma
– cancer of connective tissue (bone, fat,
cartilage) Emphysema
– loss of elasticity of Alveoli
due to cigarette
smoking
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